/Type /Annot >> endobj /Border[0 0 0]/H/I/C[1 0 0] 143 0 obj << /A << /S /GoTo /D (subsection.4.10) >> /D [114 0 R /XYZ 133.768 667.198 null] /Subtype /Link >> endobj /Rect [147.716 286.08 206.939 296.928] endstream /Border[0 0 0]/H/I/C[1 0 0] /Type /Annot /Type /Annot 122 0 obj << /Type /Annot 158 0 obj << 24 0 obj i��q�c��\vM�psl8�yIx��pf� A�� ��b�(=��1���I���@����� *��:�f��ɷ(�D�F�"��U6�0d'��)��(.fp�l�hkۻ�4��0n��t���������ue=����. /Subtype /Link /A << /S /GoTo /D (subsection.4.5) >> /Border[0 0 0]/H/I/C[1 0 0] /Border[0 0 0]/H/I/C[1 0 0] /Rect [466.521 299.972 478.476 308.385] w6[�JO��x����An� ��a���';U�;͆kSW���}�D�=Y��2����F�n�j����E/�����n�=�/�h�b�'SΌY�t��ML 6 With subdemonstrations. 4 0 obj 84 0 obj /Rect [471.502 429.487 478.476 437.899] (Negation) << /S /GoTo /D (subsection.4.5) >> 13 I had this one in an exam. Ng�;�v䒁1����e-0�kL�z(B ����dh�AgWyiϐޘ����Zr*D /Border[0 0 0]/H/I/C[1 0 0] endobj 25 0 obj /MediaBox [0 0 612 792] /Subtype /Link /Border[0 0 0]/H/I/C[1 0 0] 170 0 obj << /Rect [466.521 206.323 478.476 214.736] 8 One to think. >> endobj endobj 36 0 obj >> endobj endobj /Filter /FlateDecode /Subtype /Link << /S /GoTo /D (subsection.4.2) >> 65 0 obj /Rect [132.772 254.144 195.6 263.055] 5. /Rect [147.716 298.035 264.169 308.883] << /S /GoTo /D (section.1) >> /Border[0 0 0]/H/I/C[1 0 0] >> endobj /Type /Annot �`�$���*+�8�4�N_��Z͋��8��х�ZD�������@���ϟٛ�]�T|�1�B�? 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